Optimal. Leaf size=96 \[ -\frac{2 a^2 \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{d \left (a^2-b^2\right )^{3/2}}+\frac{a \tan (c+d x)}{d \left (a^2-b^2\right )}-\frac{b \sec (c+d x)}{d \left (a^2-b^2\right )} \]
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Rubi [A] time = 0.0988934, antiderivative size = 96, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {2727, 3767, 8, 2606, 2660, 618, 204} \[ -\frac{2 a^2 \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{d \left (a^2-b^2\right )^{3/2}}+\frac{a \tan (c+d x)}{d \left (a^2-b^2\right )}-\frac{b \sec (c+d x)}{d \left (a^2-b^2\right )} \]
Antiderivative was successfully verified.
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Rule 2727
Rule 3767
Rule 8
Rule 2606
Rule 2660
Rule 618
Rule 204
Rubi steps
\begin{align*} \int \frac{\tan ^2(c+d x)}{a+b \sin (c+d x)} \, dx &=\frac{a \int \sec ^2(c+d x) \, dx}{a^2-b^2}-\frac{a^2 \int \frac{1}{a+b \sin (c+d x)} \, dx}{a^2-b^2}-\frac{b \int \sec (c+d x) \tan (c+d x) \, dx}{a^2-b^2}\\ &=-\frac{a \operatorname{Subst}(\int 1 \, dx,x,-\tan (c+d x))}{\left (a^2-b^2\right ) d}-\frac{\left (2 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac{1}{2} (c+d x)\right )\right )}{\left (a^2-b^2\right ) d}-\frac{b \operatorname{Subst}(\int 1 \, dx,x,\sec (c+d x))}{\left (a^2-b^2\right ) d}\\ &=-\frac{b \sec (c+d x)}{\left (a^2-b^2\right ) d}+\frac{a \tan (c+d x)}{\left (a^2-b^2\right ) d}+\frac{\left (4 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac{1}{2} (c+d x)\right )\right )}{\left (a^2-b^2\right ) d}\\ &=-\frac{2 a^2 \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{\left (a^2-b^2\right )^{3/2} d}-\frac{b \sec (c+d x)}{\left (a^2-b^2\right ) d}+\frac{a \tan (c+d x)}{\left (a^2-b^2\right ) d}\\ \end{align*}
Mathematica [A] time = 0.202612, size = 152, normalized size = 1.58 \[ \frac{\sqrt{a^2-b^2} (a \sin (c+d x)+b \cos (c+d x)-b)-2 a^2 \cos (c+d x) \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{d (a-b) (a+b) \sqrt{a^2-b^2} \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right ) \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.053, size = 117, normalized size = 1.2 \begin{align*} -2\,{\frac{{a}^{2}}{d \left ( a-b \right ) \left ( a+b \right ) \sqrt{{a}^{2}-{b}^{2}}}\arctan \left ( 1/2\,{\frac{2\,a\tan \left ( 1/2\,dx+c/2 \right ) +2\,b}{\sqrt{{a}^{2}-{b}^{2}}}} \right ) }-8\,{\frac{1}{d \left ( 8\,a-8\,b \right ) \left ( \tan \left ( 1/2\,dx+c/2 \right ) +1 \right ) }}-8\,{\frac{1}{d \left ( 8\,a+8\,b \right ) \left ( \tan \left ( 1/2\,dx+c/2 \right ) -1 \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.67045, size = 684, normalized size = 7.12 \begin{align*} \left [\frac{\sqrt{-a^{2} + b^{2}} a^{2} \cos \left (d x + c\right ) \log \left (\frac{{\left (2 \, a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2} + 2 \,{\left (a \cos \left (d x + c\right ) \sin \left (d x + c\right ) + b \cos \left (d x + c\right )\right )} \sqrt{-a^{2} + b^{2}}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}\right ) - 2 \, a^{2} b + 2 \, b^{3} + 2 \,{\left (a^{3} - a b^{2}\right )} \sin \left (d x + c\right )}{2 \,{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} d \cos \left (d x + c\right )}, \frac{\sqrt{a^{2} - b^{2}} a^{2} \arctan \left (-\frac{a \sin \left (d x + c\right ) + b}{\sqrt{a^{2} - b^{2}} \cos \left (d x + c\right )}\right ) \cos \left (d x + c\right ) - a^{2} b + b^{3} +{\left (a^{3} - a b^{2}\right )} \sin \left (d x + c\right )}{{\left (a^{4} - 2 \, a^{2} b^{2} + b^{4}\right )} d \cos \left (d x + c\right )}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\tan ^{2}{\left (c + d x \right )}}{a + b \sin{\left (c + d x \right )}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.05295, size = 144, normalized size = 1.5 \begin{align*} -\frac{2 \,{\left (\frac{{\left (\pi \left \lfloor \frac{d x + c}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (a\right ) + \arctan \left (\frac{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + b}{\sqrt{a^{2} - b^{2}}}\right )\right )} a^{2}}{{\left (a^{2} - b^{2}\right )}^{\frac{3}{2}}} + \frac{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - b}{{\left (a^{2} - b^{2}\right )}{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}}\right )}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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